{"version":2,"relationshipURLBase":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html","relationshipResolution":"Resolve relative relationship URLs against relationshipURLBase; complete records and absolute URLs are in blocks.","title":"十六个图块，只有四个进入编码器","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html","markdown":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.md","pages":[{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","unit":"限制可见信息，怎样构成可验证的重建任务？","unitId":"i-masked-prediction","chapter":"I","number":1}],"aliases":[{"oldId":"explanation","targetId":"h-i-mae-visible-input-and-cost","operation":"split-explanation-range"},{"oldId":"b-72c7bee21e1f967fd045073b","targetId":"b-72c7bee21e1f967fd045073b","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"d71cf15e707c8a3674b4c90a599efee783cb84da5b8c8236a1d01c3add7b4958","afterSHA256":"d71cf15e707c8a3674b4c90a599efee783cb84da5b8c8236a1d01c3add7b4958","reason":"Same source body in authored semantic page"},{"oldId":"b-c97044c29f496a2045ad0587","targetId":"b-c97044c29f496a2045ad0587","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"6d7bc4638fcdfc4fe5380432557660fb72192db2cc9655e74ec3a3d01969c994","afterSHA256":"6d7bc4638fcdfc4fe5380432557660fb72192db2cc9655e74ec3a3d01969c994","reason":"Same source body in authored semantic page"},{"oldId":"b-597917ea6d095d22c07eb79a","targetId":"b-597917ea6d095d22c07eb79a","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"1f23436418bb9306bc343705135fc831445c2db90a17e4b6fef6e31a4889b2d4","afterSHA256":"1f23436418bb9306bc343705135fc831445c2db90a17e4b6fef6e31a4889b2d4","reason":"Same source body in authored semantic page"},{"oldId":"b-eec1d081059ffee8eaa76b75","targetId":"b-eec1d081059ffee8eaa76b75","page":"h-i-mae-visible-input-and-cost","operation":"rewrite","beforeSHA256":"96fe3889bbaf9b3289dbfe42a0b331e94414b00de270f5b5b924c9647d4d2fa4","afterSHA256":"2e7c1e66199b2d4003a65364b0e57ffadc3ab5a102401491d80455ed0717fa89","reason":"Same source identity with figure semantics or reading context enriched"},{"oldId":"b-2a82662d5b65e5e8bcce1ff1","targetId":"b-2a82662d5b65e5e8bcce1ff1","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"786ce10a6b32a492259a3dccd0a54e61cd41d28a34382fb7b5386c5f03b7ad69","afterSHA256":"786ce10a6b32a492259a3dccd0a54e61cd41d28a34382fb7b5386c5f03b7ad69","reason":"Same source body in authored semantic page"},{"oldId":"b-318bdbec21f6c32e02ba580a","targetId":"b-318bdbec21f6c32e02ba580a","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"ce1c803ad8d347ed4ce40862d193164f743f68754b0ed85ef68b09ad2626e699","afterSHA256":"ce1c803ad8d347ed4ce40862d193164f743f68754b0ed85ef68b09ad2626e699","reason":"Same source body in authored semantic page"},{"oldId":"b-b2bd47e4f6aac27987104eee","targetId":"b-b2bd47e4f6aac27987104eee","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"cf0c91f6391a43ba4d537fd194b09b2b84b49faabab68eb206a78a15f8795d86","afterSHA256":"cf0c91f6391a43ba4d537fd194b09b2b84b49faabab68eb206a78a15f8795d86","reason":"Same source body in authored semantic page"},{"oldId":"b-7df39a49d2924acfd99ebfe5","targetId":"b-7df39a49d2924acfd99ebfe5","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"1b9de6a03a13a44934b26de3efa8729d58652ba2acef85b5b94b18a2b298dc2f","afterSHA256":"1b9de6a03a13a44934b26de3efa8729d58652ba2acef85b5b94b18a2b298dc2f","reason":"Same source body in authored semantic page"},{"oldId":"b-3963626a02cbc61bc6663cb1","targetId":"b-3963626a02cbc61bc6663cb1","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"0b608cd258c9d8db627cfb6ba9a76edcadb2b5ba7dea9cdc03859cc921f42f49","afterSHA256":"0b608cd258c9d8db627cfb6ba9a76edcadb2b5ba7dea9cdc03859cc921f42f49","reason":"Same source body in authored semantic page"},{"oldId":"b-74bfb9b0403fcbf560b9fe36","targetId":"b-74bfb9b0403fcbf560b9fe36","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"2aad84e8bf5a05c2ce78d7bf60aa1e13a6b88c2655ee5be7ddad92318d5f22c6","afterSHA256":"2aad84e8bf5a05c2ce78d7bf60aa1e13a6b88c2655ee5be7ddad92318d5f22c6","reason":"Same source body in authored semantic page"},{"oldId":"b-9f497c138916813b160692e1","targetId":"b-9f497c138916813b160692e1","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"2fc080327dbb4b439fadf2d8d55c7faf96333211c0513cb4ce6091f11b72f9f3","afterSHA256":"2fc080327dbb4b439fadf2d8d55c7faf96333211c0513cb4ce6091f11b72f9f3","reason":"Same source body in authored semantic page"},{"oldId":"b-4d53298697a589de39faf60a","targetId":"b-4d53298697a589de39faf60a","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"cc473fa139d18e11032f1324021e26cb652f176eea094563108edb596633713f","afterSHA256":"cc473fa139d18e11032f1324021e26cb652f176eea094563108edb596633713f","reason":"Same source body in authored semantic page"},{"oldId":"b-d6acb6e18e120c19ac46d643","targetId":"b-d6acb6e18e120c19ac46d643","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"6fc2fb8abfdb5f7436d70e82bcc6a6060bf84c7c6704187c4857eee18e665fcf","afterSHA256":"6fc2fb8abfdb5f7436d70e82bcc6a6060bf84c7c6704187c4857eee18e665fcf","reason":"Same source body in authored semantic page"},{"oldId":"b-e2c63f82f07bc556a7292fd0","targetId":"b-e2c63f82f07bc556a7292fd0","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"7d544fa2fae3bc12754501c9fe5a9917304b891164941a690c8a82d8433c8680","afterSHA256":"7d544fa2fae3bc12754501c9fe5a9917304b891164941a690c8a82d8433c8680","reason":"Same source body in authored semantic page"},{"oldId":"b-2883de397cccc245893658c9","targetId":"b-2883de397cccc245893658c9","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"cf44fcc62782fb4f6bdc42c16c5187d57556a03cb7ce6065e7bd9c36d8e7d733","afterSHA256":"cf44fcc62782fb4f6bdc42c16c5187d57556a03cb7ce6065e7bd9c36d8e7d733","reason":"Same source body in authored semantic page"},{"oldId":"b-4261f2291e6a7061511c8b81","targetId":"b-4261f2291e6a7061511c8b81","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"7744576f3b81592d96ab8c823333e07ea440828e55b57671927ae3dd80d6af78","afterSHA256":"7744576f3b81592d96ab8c823333e07ea440828e55b57671927ae3dd80d6af78","reason":"Same source body in authored semantic page"},{"oldId":"b-bf01aa31f3da7caffaf5b954","targetId":"b-bf01aa31f3da7caffaf5b954","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"6087a86c928830c15bd1d1a7c843c96c6b998f426e17e812d41681e31dbe77ca","afterSHA256":"6087a86c928830c15bd1d1a7c843c96c6b998f426e17e812d41681e31dbe77ca","reason":"Same source body in authored semantic page"},{"oldId":"b-18768777718949a7253460bb","targetId":"b-18768777718949a7253460bb","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"cf73c01076925a5e74b576002275ab3828cc3396e6263d59f72f56144f220701","afterSHA256":"cf73c01076925a5e74b576002275ab3828cc3396e6263d59f72f56144f220701","reason":"Same source body in authored semantic page"},{"oldId":"b-3c063211ea91fad6ed1d5fe8","targetId":"b-3c063211ea91fad6ed1d5fe8","page":"h-i-mae-visible-input-and-cost","operation":"move","beforeSHA256":"cf73c01076925a5e74b576002275ab3828cc3396e6263d59f72f56144f220701","afterSHA256":"cf73c01076925a5e74b576002275ab3828cc3396e6263d59f72f56144f220701","reason":"Same source body in authored semantic page"},{"oldId":"h-i-mae-visible-input-and-cost-title","targetId":"b-a40ba14299ed0e22881b2179","operation":"retain-source-identity"}],"blocks":[{"id":"b-a40ba14299ed0e22881b2179","type":"h2","scope":"h-i-mae-visible-input-and-cost","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-a40ba14299ed0e22881b2179","content":"## 只编码四个可见块，同时保留原始位置","sha256":"90aabf175653892227d9ecef6d86067838d7963786dbaa4e1038ca1bd6a78d6c","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"previousBlock":null,"nextBlock":"b-72c7bee21e1f967fd045073b","prerequisites":[{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"}]},{"id":"b-72c7bee21e1f967fd045073b","type":"h2","scope":"explanation","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-72c7bee21e1f967fd045073b","content":"## 解释、算例与证据","sha256":"d71cf15e707c8a3674b4c90a599efee783cb84da5b8c8236a1d01c3add7b4958","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-a40ba14299ed0e22881b2179","nextBlock":"b-c97044c29f496a2045ad0587","prerequisites":[{"id":"b-a40ba14299ed0e22881b2179","url":"#b-a40ba14299ed0e22881b2179","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"}]},{"id":"b-c97044c29f496a2045ad0587","type":"h1","scope":"document","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-c97044c29f496a2045ad0587","content":"# P20 · 十六个图块，只有四个进入编码器","sha256":"6d7bc4638fcdfc4fe5380432557660fb72192db2cc9655e74ec3a3d01969c994","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-72c7bee21e1f967fd045073b","nextBlock":"b-597917ea6d095d22c07eb79a","prerequisites":[{"id":"b-72c7bee21e1f967fd045073b","url":"#b-72c7bee21e1f967fd045073b","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"}]},{"id":"b-597917ea6d095d22c07eb79a","type":"p","scope":"document","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-597917ea6d095d22c07eb79a","content":"固定16块与4个可见位置，让编码器输入可以逐项指认；计算节省与隐藏比例的关系留在本页说明。","sha256":"1f23436418bb9306bc343705135fc831445c2db90a17e4b6fef6e31a4889b2d4","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-c97044c29f496a2045ad0587","nextBlock":"b-eec1d081059ffee8eaa76b75","prerequisites":[{"id":"b-c97044c29f496a2045ad0587","url":"#b-c97044c29f496a2045ad0587","role":"section-title"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"}]},{"id":"b-eec1d081059ffee8eaa76b75","type":"figure","scope":"document","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-eec1d081059ffee8eaa76b75","content":"图内标签与数值：P20 学习表示机制图，状态 2；MAE 教学网格 · 16 块中保留 0、3、9、14；0；1；2；3；4；5；6；7；8；9；10；11；12；13；14；15；4 块可见，12 块隐藏；块 0；位置 0；块 3；位置 3；块 9；位置 9；块 14；位置 14；编码器只处理这 4 块；隐藏位置不送入 mask token；4 / 16 是输入块数量；并不等于整个系统必然加速 4 倍。\n\n4×4共16块，固定可见0、3、9、14四块携位置进入编码器，12个隐藏块不输入。\n\n- MAE 教学网格 · 16 块中保留 0、3、9、14\n- 0\n- 1\n- 2\n- 3\n- 4\n- 5\n- 6\n- 7\n- 8\n- 9\n- 10\n- 11\n- 12\n- 13\n- 14\n- 15\n- 4 块可见，12 块隐藏\n- 块 0\n- 位置 0\n- 块 3\n- 位置 3\n- 块 9\n- 位置 9\n- 块 14\n- 位置 14\n- 编码器只处理这 4 块\n- 隐藏位置不送入 mask token\n- 4 / 16 是输入块数量；并不等于整个系统必然加速 4 倍。4×4共16块，固定可见0、3、9、14四块携位置进入编码器，12个隐藏块不输入。 [查看对应图解状态](/#/l3-r2-p20/1)[查看完整图解](/course/figures/l3-r2-p20-1.html)","sha256":"2e7c1e66199b2d4003a65364b0e57ffadc3ab5a102401491d80455ed0717fa89","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"figure":{"caption":"4×4共16块，固定可见0、3、9、14四块携位置进入编码器，12个隐藏块不输入。 查看对应图解状态","labels":["MAE 教学网格 · 16 块中保留 0、3、9、14","0","1","2","3","4","5","6","7","8","9","10","11","12","13","14","15","4 块可见，12 块隐藏","块 0","位置 0","块 3","位置 3","块 9","位置 9","块 14","位置 14","编码器只处理这 4 块","隐藏位置不送入 mask token","4 / 16 是输入块数量；并不等于整个系统必然加速 4 倍。"],"description":"4×4共16块，固定可见0、3、9、14四块携位置进入编码器，12个隐藏块不输入。MAE 教学网格 · 16 块中保留 0、3、9、1401234567891011121314154 块可见，12 块隐藏块 0位置 0块 3位置 3块 9位置 9块 14位置 14编码器只处理这 4 块隐藏位置不送入 mask token4 / 16 是输入块数量；并不等于整个系统必然加速 4 倍。","evidenceIdentity":"4×4共16块，固定可见0、3、9、14四块携位置进入编码器，12个隐藏块不输入。 查看对应图解状态","images":[{"src":"/assets/display/584c419ba431799ff41df983.webp","alt":""}]},"previousBlock":"b-597917ea6d095d22c07eb79a","nextBlock":"b-2a82662d5b65e5e8bcce1ff1","prerequisites":[{"id":"b-c97044c29f496a2045ad0587","url":"#b-c97044c29f496a2045ad0587","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[]},{"id":"b-2a82662d5b65e5e8bcce1ff1","type":"h2","scope":"narrative","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-2a82662d5b65e5e8bcce1ff1","content":"## 课堂讲述","sha256":"786ce10a6b32a492259a3dccd0a54e61cd41d28a34382fb7b5386c5f03b7ad69","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-eec1d081059ffee8eaa76b75","nextBlock":"b-318bdbec21f6c32e02ba580a","prerequisites":[{"id":"b-c97044c29f496a2045ad0587","url":"#b-c97044c29f496a2045ad0587","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"}]},{"id":"b-318bdbec21f6c32e02ba580a","type":"p","scope":"narrative","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-318bdbec21f6c32e02ba580a","content":"为便于观察，把这张图分成十六个图块，遮掉十二个，也就是四分之三。编码器只处理剩下四块，而不是把全部十六个位置都送进去再告诉它哪些是空的。\n每个可见图块变成向量，并保留位置线索。这里我们只需要把编码器理解成将可见块组织成表示的网络，不在今天打开 Transformer 内部。\n这个结构同时回应学习与计算：任务要求根据少量可见内容推测隐藏部分；昂贵的编码器又少处理了很多输入。注意，十六变四不代表整个系统必然加速四倍，其他计算仍然存在。现在先看清信息流，再看缺失位置怎样回到解码端。","sha256":"ce1c803ad8d347ed4ce40862d193164f743f68754b0ed85ef68b09ad2626e699","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-2a82662d5b65e5e8bcce1ff1","nextBlock":"b-b2bd47e4f6aac27987104eee","prerequisites":[{"id":"b-2a82662d5b65e5e8bcce1ff1","url":"#b-2a82662d5b65e5e8bcce1ff1","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"}]},{"id":"b-b2bd47e4f6aac27987104eee","type":"h3","scope":"mae-visible-patch-input","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-b2bd47e4f6aac27987104eee","content":"### 16 块中，编码器真的只看见 4 块","sha256":"cf0c91f6391a43ba4d537fd194b09b2b84b49faabab68eb206a78a15f8795d86","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"16 块中，编码器真的只看见 4 块","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":"mae-visible-patch-input","formulas":[],"previousBlock":"b-318bdbec21f6c32e02ba580a","nextBlock":"b-7df39a49d2924acfd99ebfe5","prerequisites":[{"id":"b-2a82662d5b65e5e8bcce1ff1","url":"#b-2a82662d5b65e5e8bcce1ff1","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"},{"id":"b-7df39a49d2924acfd99ebfe5","url":"#b-7df39a49d2924acfd99ebfe5","relation":"same-reasoning"},{"id":"b-3963626a02cbc61bc6663cb1","url":"#b-3963626a02cbc61bc6663cb1","relation":"same-reasoning"},{"id":"b-74bfb9b0403fcbf560b9fe36","url":"#b-74bfb9b0403fcbf560b9fe36","relation":"same-reasoning"}]},{"id":"b-7df39a49d2924acfd99ebfe5","type":"p","scope":"mae-visible-patch-input","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-7df39a49d2924acfd99ebfe5","content":"当前图把原图切为4×4网格，位置编号0–15，可见集合固定为{0,3,9,14}，其余12块隐藏。原图仍由数据管线保存，供损失比较；它不作为完整输入偷偷进入编码器。","sha256":"1b9de6a03a13a44934b26de3efa8729d58652ba2acef85b5b94b18a2b298dc2f","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"16 块中，编码器真的只看见 4 块","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":"mae-visible-patch-input","formulas":[],"previousBlock":"b-b2bd47e4f6aac27987104eee","nextBlock":"b-3963626a02cbc61bc6663cb1","prerequisites":[{"id":"b-b2bd47e4f6aac27987104eee","url":"#b-b2bd47e4f6aac27987104eee","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"},{"id":"b-b2bd47e4f6aac27987104eee","url":"#b-b2bd47e4f6aac27987104eee","relation":"same-reasoning"},{"id":"b-3963626a02cbc61bc6663cb1","url":"#b-3963626a02cbc61bc6663cb1","relation":"same-reasoning"},{"id":"b-74bfb9b0403fcbf560b9fe36","url":"#b-74bfb9b0403fcbf560b9fe36","relation":"same-reasoning"}]},{"id":"b-3963626a02cbc61bc6663cb1","type":"p","scope":"mae-visible-patch-input","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-3963626a02cbc61bc6663cb1","content":"可见patch转换成向量，并带着原始位置线索进入编码器。这里的位置不能压成“现在队列中的第1、2、3、4项”：位置0与位置14在原图的含义不同。输出表示还要能够放回原来的空间位置。","sha256":"0b608cd258c9d8db627cfb6ba9a76edcadb2b5ba7dea9cdc03859cc921f42f49","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"16 块中，编码器真的只看见 4 块","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":"mae-visible-patch-input","formulas":[],"previousBlock":"b-7df39a49d2924acfd99ebfe5","nextBlock":"b-74bfb9b0403fcbf560b9fe36","prerequisites":[{"id":"b-b2bd47e4f6aac27987104eee","url":"#b-b2bd47e4f6aac27987104eee","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"},{"id":"b-b2bd47e4f6aac27987104eee","url":"#b-b2bd47e4f6aac27987104eee","relation":"same-reasoning"},{"id":"b-7df39a49d2924acfd99ebfe5","url":"#b-7df39a49d2924acfd99ebfe5","relation":"same-reasoning"},{"id":"b-74bfb9b0403fcbf560b9fe36","url":"#b-74bfb9b0403fcbf560b9fe36","relation":"same-reasoning"}]},{"id":"b-74bfb9b0403fcbf560b9fe36","type":"p","scope":"mae-visible-patch-input","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-74bfb9b0403fcbf560b9fe36","content":"4/16是课堂上说明75%遮挡的简单图。随机遮挡会让训练中的可见集合变化；当前固定集合是便于逐项追踪的一个样本。原MAE的非对称设计关键在于让较重编码器只处理可见项，而不是在完整图编码之后才把12块涂黑。","sha256":"2aad84e8bf5a05c2ce78d7bf60aa1e13a6b88c2655ee5be7ddad92318d5f22c6","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"16 块中，编码器真的只看见 4 块","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":"mae-visible-patch-input","formulas":[],"previousBlock":"b-3963626a02cbc61bc6663cb1","nextBlock":"b-9f497c138916813b160692e1","prerequisites":[{"id":"b-b2bd47e4f6aac27987104eee","url":"#b-b2bd47e4f6aac27987104eee","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"},{"id":"b-b2bd47e4f6aac27987104eee","url":"#b-b2bd47e4f6aac27987104eee","relation":"same-reasoning"},{"id":"b-7df39a49d2924acfd99ebfe5","url":"#b-7df39a49d2924acfd99ebfe5","relation":"same-reasoning"},{"id":"b-3963626a02cbc61bc6663cb1","url":"#b-3963626a02cbc61bc6663cb1","relation":"same-reasoning"}]},{"id":"b-9f497c138916813b160692e1","type":"h3","scope":"mae-compute-not-sixteen-times","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-9f497c138916813b160692e1","content":"### 少看图块为何省计算，又为何不是固定加速比","sha256":"2fc080327dbb4b439fadf2d8d55c7faf96333211c0513cb4ce6091f11b72f9f3","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"少看图块为何省计算，又为何不是固定加速比","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":"mae-compute-not-sixteen-times","formulas":[],"previousBlock":"b-74bfb9b0403fcbf560b9fe36","nextBlock":"b-4d53298697a589de39faf60a","prerequisites":[{"id":"b-b2bd47e4f6aac27987104eee","url":"#b-b2bd47e4f6aac27987104eee","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"},{"id":"b-4d53298697a589de39faf60a","url":"#b-4d53298697a589de39faf60a","relation":"same-reasoning"},{"id":"b-d6acb6e18e120c19ac46d643","url":"#b-d6acb6e18e120c19ac46d643","relation":"same-reasoning"},{"id":"b-e2c63f82f07bc556a7292fd0","url":"#b-e2c63f82f07bc556a7292fd0","relation":"same-reasoning"}]},{"id":"b-4d53298697a589de39faf60a","type":"p","scope":"mae-compute-not-sixteen-times","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-4d53298697a589de39faf60a","content":"16块只保留4块，编码器处理的项数变为四分之一。一些逐项计算随项数下降；涉及两两位置的计算从16²降为4²，是原来的1/16。这可以解释为什么高遮挡率有计算价值，但不需要在本讲展开注意力算法。","sha256":"cc473fa139d18e11032f1324021e26cb652f176eea094563108edb596633713f","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"少看图块为何省计算，又为何不是固定加速比","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":"mae-compute-not-sixteen-times","formulas":[],"previousBlock":"b-9f497c138916813b160692e1","nextBlock":"b-d6acb6e18e120c19ac46d643","prerequisites":[{"id":"b-9f497c138916813b160692e1","url":"#b-9f497c138916813b160692e1","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"},{"id":"b-9f497c138916813b160692e1","url":"#b-9f497c138916813b160692e1","relation":"same-reasoning"},{"id":"b-d6acb6e18e120c19ac46d643","url":"#b-d6acb6e18e120c19ac46d643","relation":"same-reasoning"},{"id":"b-e2c63f82f07bc556a7292fd0","url":"#b-e2c63f82f07bc556a7292fd0","relation":"same-reasoning"}]},{"id":"b-d6acb6e18e120c19ac46d643","type":"p","scope":"mae-compute-not-sixteen-times","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-d6acb6e18e120c19ac46d643","content":"整个训练还包含patch转换、其他网络层、解码器、损失和硬件调度。解码器重新处理完整位置，因此端到端耗时不等于某个二次项的比值。课堂上“16倍”只可描述这个构造的两两项数变化，不能宣称实际训练快16倍。","sha256":"6fc2fb8abfdb5f7436d70e82bcc6a6060bf84c7c6704187c4857eee18e665fcf","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"少看图块为何省计算，又为何不是固定加速比","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":"mae-compute-not-sixteen-times","formulas":[],"previousBlock":"b-4d53298697a589de39faf60a","nextBlock":"b-e2c63f82f07bc556a7292fd0","prerequisites":[{"id":"b-9f497c138916813b160692e1","url":"#b-9f497c138916813b160692e1","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"},{"id":"b-9f497c138916813b160692e1","url":"#b-9f497c138916813b160692e1","relation":"same-reasoning"},{"id":"b-4d53298697a589de39faf60a","url":"#b-4d53298697a589de39faf60a","relation":"same-reasoning"},{"id":"b-e2c63f82f07bc556a7292fd0","url":"#b-e2c63f82f07bc556a7292fd0","relation":"same-reasoning"}]},{"id":"b-e2c63f82f07bc556a7292fd0","type":"p","scope":"mae-compute-not-sixteen-times","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-e2c63f82f07bc556a7292fd0","content":"当前LAB 08用稠密卷积网格加mask通道，仍处理完整8×8图像；它能教遮挡目标与评价，但不能复现原MAE可见token编码器的计算节省。方法机制与教学模型的对应范围应这样逐项标清。","sha256":"7d544fa2fae3bc12754501c9fe5a9917304b891164941a690c8a82d8433c8680","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"少看图块为何省计算，又为何不是固定加速比","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":"mae-compute-not-sixteen-times","formulas":[],"previousBlock":"b-d6acb6e18e120c19ac46d643","nextBlock":"b-2883de397cccc245893658c9","prerequisites":[{"id":"b-9f497c138916813b160692e1","url":"#b-9f497c138916813b160692e1","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"},{"id":"b-9f497c138916813b160692e1","url":"#b-9f497c138916813b160692e1","relation":"same-reasoning"},{"id":"b-4d53298697a589de39faf60a","url":"#b-4d53298697a589de39faf60a","relation":"same-reasoning"},{"id":"b-d6acb6e18e120c19ac46d643","url":"#b-d6acb6e18e120c19ac46d643","relation":"same-reasoning"}]},{"id":"b-2883de397cccc245893658c9","type":"h2","scope":"practice","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-2883de397cccc245893658c9","content":"## 沿这个问题继续","sha256":"cf44fcc62782fb4f6bdc42c16c5187d57556a03cb7ce6065e7bd9c36d8e7d733","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-e2c63f82f07bc556a7292fd0","nextBlock":"b-4261f2291e6a7061511c8b81","prerequisites":[{"id":"b-9f497c138916813b160692e1","url":"#b-9f497c138916813b160692e1","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"}]},{"id":"b-4261f2291e6a7061511c8b81","type":"p","scope":"practice","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-4261f2291e6a7061511c8b81","content":"对照LAB 08最后的原MAE比较表，明确教学ConvAE仍处理稠密网格；不要拿它测原MAE加速。","sha256":"7744576f3b81592d96ab8c823333e07ea440828e55b57671927ae3dd80d6af78","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-2883de397cccc245893658c9","nextBlock":"b-17088c6fe5182aaf838ebe1a","prerequisites":[{"id":"b-2883de397cccc245893658c9","url":"#b-2883de397cccc245893658c9","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"}]},{"id":"b-17088c6fe5182aaf838ebe1a","type":"h4","scope":"h-i-mae-visible-input-and-cost","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-17088c6fe5182aaf838ebe1a","content":"#### 图示条件与公式约定","sha256":"ef7f915c1ae63ed67bd23fecf050249273ba0efa8965d2c8d1c1c6b2d3178122","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-4261f2291e6a7061511c8b81","nextBlock":"b-bf01aa31f3da7caffaf5b954","prerequisites":[{"id":"b-2883de397cccc245893658c9","url":"#b-2883de397cccc245893658c9","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"}]},{"id":"b-bf01aa31f3da7caffaf5b954","type":"p","scope":"document","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-bf01aa31f3da7caffaf5b954","content":"块索引按从左到右、从上到下的0至15。可见集合={0,3,9,14}，隐藏比例=12/16=.75。现实预训练随机采样，此处固定采样结果以便追踪。","sha256":"6087a86c928830c15bd1d1a7c843c96c6b998f426e17e812d41681e31dbe77ca","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-17088c6fe5182aaf838ebe1a","nextBlock":"b-5b4516cbe0e6b9e5f2c12dbc","prerequisites":[{"id":"b-17088c6fe5182aaf838ebe1a","url":"#b-17088c6fe5182aaf838ebe1a","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"}]},{"id":"b-5b4516cbe0e6b9e5f2c12dbc","type":"h4","scope":"retained-reading","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-5b4516cbe0e6b9e5f2c12dbc","content":"#### 这条线索的展开与后续阅读","sha256":"48b8229f7559b36ed4d5628416e3991e5c73293fbce43374db67386c8736f3bc","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-bf01aa31f3da7caffaf5b954","nextBlock":"b-18768777718949a7253460bb","prerequisites":[{"id":"b-17088c6fe5182aaf838ebe1a","url":"#b-17088c6fe5182aaf838ebe1a","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"}]},{"id":"b-18768777718949a7253460bb","type":"ul","scope":"retained-reading","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-18768777718949a7253460bb","content":"- [MAE：只编码可见块，再回到完整位置](/supplement.html?return=l3-r2-p20/0#/l3-mae/0) 本页说明","sha256":"cf73c01076925a5e74b576002275ab3828cc3396e6263d59f72f56144f220701","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-5b4516cbe0e6b9e5f2c12dbc","nextBlock":"b-3c063211ea91fad6ed1d5fe8","prerequisites":[{"id":"b-5b4516cbe0e6b9e5f2c12dbc","url":"#b-5b4516cbe0e6b9e5f2c12dbc","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"}]},{"id":"b-3c063211ea91fad6ed1d5fe8","type":"li","scope":"retained-reading","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p20.html#b-3c063211ea91fad6ed1d5fe8","content":"- [MAE：只编码可见块，再回到完整位置](/supplement.html?return=l3-r2-p20/0#/l3-mae/0) 本页说明","sha256":"cf73c01076925a5e74b576002275ab3828cc3396e6263d59f72f56144f220701","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-masked-prediction","title":"限制可见信息，怎样构成可验证的重建任务？"},"page":{"id":"h-i-mae-visible-input-and-cost","title":"只编码四个可见块，同时保留原始位置","number":1},"sectionTitle":"只编码四个可见块，同时保留原始位置","currentQuestion":"限制可见信息，怎样构成可验证的重建任务？","sourceSlides":["l3-r2-p20"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-18768777718949a7253460bb","nextBlock":null,"prerequisites":[{"id":"b-5b4516cbe0e6b9e5f2c12dbc","url":"#b-5b4516cbe0e6b9e5f2c12dbc","role":"section-title"},{"id":"b-597917ea6d095d22c07eb79a","url":"#b-597917ea6d095d22c07eb79a","role":"problem-context"}],"relatedBlocks":[{"id":"b-eec1d081059ffee8eaa76b75","url":"#b-eec1d081059ffee8eaa76b75","relation":"figure-and-explanation"}]}]}