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先看轴身份，再数每行的候选","sha256":"a415d89372ab26b5e2f145547b7cabd21b3e72620f8765e09ce9e02b0eb05d0d","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-dictionary-and-updates","title":"怎样增加候选，同时让历史表示仍可比较？"},"page":{"id":"h-i-batch-candidate-matrix","title":"先看轴身份，再数每行的候选","number":1},"sectionTitle":"先看轴身份，再数每行的候选","currentQuestion":"怎样增加候选，同时让历史表示仍可比较？","sourceSlides":["l3-r2-p14"],"knowledgeBlock":null,"formulas":[],"previousBlock":null,"nextBlock":"b-9fd3ffc4db5a2bdaa8d06fad","prerequisites":[{"id":"b-af32f72cdac67dd0fd356861","url":"#b-af32f72cdac67dd0fd356861","role":"problem-context"}],"relatedBlocks":[{"id":"b-90d0ce9c0f9ec31c3366799b","url":"#b-90d0ce9c0f9ec31c3366799b","relation":"figure-and-explanation"}]},{"id":"b-9fd3ffc4db5a2bdaa8d06fad","type":"h2","scope":"explanation","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p14.html#b-9fd3ffc4db5a2bdaa8d06fad","content":"## 解释、算例与证据","sha256":"d71cf15e707c8a3674b4c90a599efee783cb84da5b8c8236a1d01c3add7b4958","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-dictionary-and-updates","title":"怎样增加候选，同时让历史表示仍可比较？"},"page":{"id":"h-i-batch-candidate-matrix","title":"先看轴身份，再数每行的候选","number":1},"sectionTitle":"先看轴身份，再数每行的候选","currentQuestion":"怎样增加候选，同时让历史表示仍可比较？","sourceSlides":["l3-r2-p14"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-51e7428c7ff1dd3ca032bbd7","nextBlock":"b-b233673a1cd0f75a0fba7dd2","prerequisites":[{"id":"b-51e7428c7ff1dd3ca032bbd7","url":"#b-51e7428c7ff1dd3ca032bbd7","role":"section-title"},{"id":"b-af32f72cdac67dd0fd356861","url":"#b-af32f72cdac67dd0fd356861","role":"problem-context"}],"relatedBlocks":[{"id":"b-90d0ce9c0f9ec31c3366799b","url":"#b-90d0ce9c0f9ec31c3366799b","relation":"figure-and-explanation"}]},{"id":"b-b233673a1cd0f75a0fba7dd2","type":"h1","scope":"document","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p14.html#b-b233673a1cd0f75a0fba7dd2","content":"# P14 · 比较更多候选，代价在哪里？","sha256":"5005686a32f803139fdb5015f96545ef9d6d68dafa23203a1280b64f295246d8","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-dictionary-and-updates","title":"怎样增加候选，同时让历史表示仍可比较？"},"page":{"id":"h-i-batch-candidate-matrix","title":"先看轴身份，再数每行的候选","number":1},"sectionTitle":"先看轴身份，再数每行的候选","currentQuestion":"怎样增加候选，同时让历史表示仍可比较？","sourceSlides":["l3-r2-p14"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-9fd3ffc4db5a2bdaa8d06fad","nextBlock":"b-af32f72cdac67dd0fd356861","prerequisites":[{"id":"b-9fd3ffc4db5a2bdaa8d06fad","url":"#b-9fd3ffc4db5a2bdaa8d06fad","role":"section-title"},{"id":"b-af32f72cdac67dd0fd356861","url":"#b-af32f72cdac67dd0fd356861","role":"problem-context"}],"relatedBlocks":[{"id":"b-90d0ce9c0f9ec31c3366799b","url":"#b-90d0ce9c0f9ec31c3366799b","relation":"figure-and-explanation"}]},{"id":"b-af32f72cdac67dd0fd356861","type":"p","scope":"document","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p14.html#b-af32f72cdac67dd0fd356861","content":"从同一个视图列表指认查询、自身和正例：4×4 到 6×6，每行候选从 3 项到 5 项。随后再把候选来源转为计算组织问题，为 MoCo 队列做铺垫。","sha256":"628eb576124e20c5dc90d67d278cd3144ad68ffd5693c89d66f7ad111a740ed5","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-dictionary-and-updates","title":"怎样增加候选，同时让历史表示仍可比较？"},"page":{"id":"h-i-batch-candidate-matrix","title":"先看轴身份，再数每行的候选","number":1},"sectionTitle":"先看轴身份，再数每行的候选","currentQuestion":"怎样增加候选，同时让历史表示仍可比较？","sourceSlides":["l3-r2-p14"],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-b233673a1cd0f75a0fba7dd2","nextBlock":"b-90d0ce9c0f9ec31c3366799b","prerequisites":[{"id":"b-b233673a1cd0f75a0fba7dd2","url":"#b-b233673a1cd0f75a0fba7dd2","role":"section-title"}],"relatedBlocks":[{"id":"b-90d0ce9c0f9ec31c3366799b","url":"#b-90d0ce9c0f9ec31c3366799b","relation":"figure-and-explanation"}]},{"id":"b-90d0ce9c0f9ec31c3366799b","type":"figure","scope":"document","url":"https://codingai-lec03.pages.dev/course/pages/l3-r2-p14.html#b-90d0ce9c0f9ec31c3366799b","content":"图内标签与数值：P14 同一视图列表的 6×6 对比矩阵：自身排除、同源正例与其他候选；全部来自当前批次；能否复用历史特征？；3 张原图 → 6 个视图；原图 A；A1；A2；原图 B；B1；B2；原图 C；C1；C2；两轴使用同一个视图列表；行表示查询；A1；+；A2；+；B1；+；B2；+；C1；+；C2；+；A1；A2；B1；B2；C1；C2；固定查询 A1；A1：自身，排除；A2：同源正例；B1、B2、C1、C2：其余候选；每行：1 + 4 = 5 项；自身排除；同源正例；2N−2 个其余候选；当前编码 6 个视图；完整比较矩阵 6 × 6（随 2N 平方增长）。；下一方法：MoCo 的取舍；先问能否保存已算的 key；复用旧向量，减少本轮编码；候选数与当前批次能否解耦？；旧键还足够可比吗？\n\n当前批次从原图 A、B 的 A1/A2/B1/B2 四视图（4×4）扩为 A、B、C 的六视图（6×6）。矩阵两轴使用同一视图列表，灰色斜线主对角为自身并排除；每行只有同源的另一个视图为绿色正例，其余 2N−2 个为其他候选。A1 行显示全部候选身份。右侧将复用历史 key 作为下一方法 MoCo 的资源取舍。\n\n- 全部来自当前批次\n- 能否复用历史特征？\n- 3 张原图 → 6 个视图\n- 原图 A\n- A1\n- A2\n- 原图 B\n- B1\n- B2\n- 原图 C\n- C1\n- C2\n- 两轴使用同一个视图列表；行表示查询\n- A1\n- +\n- A2\n- +\n- B1\n- +\n- B2\n- +\n- C1\n- +\n- C2\n- +\n- A1\n- A2\n- B1\n- B2\n- C1\n- C2\n- 固定查询 A1\n- A1：自身，排除\n- A2：同源正例\n- B1、B2、C1、C2：其余候选\n- 每行：1 + 4 = 5 项\n- 自身排除\n- 同源正例\n- 2N−2 个其余候选\n- 当前编码 6 个视图；完整比较矩阵 6 × 6（随 2N 平方增长）。\n- 下一方法：MoCo 的取舍\n- 先问能否保存已算的 key\n- 复用旧向量，减少本轮编码\n- 候选数与当前批次能否解耦？\n- 旧键还足够可比吗？当前批次从原图 A、B 的 A1/A2/B1/B2 四视图（4×4）扩为 A、B、C 的六视图（6×6）。矩阵两轴使用同一视图列表，灰色斜线主对角为自身并排除；每行只有同源的另一个视图为绿色正例，其余 2N−2 个为其他候选。A1 行显示全部候选身份。右侧将复用历史 key 作为下一方法 MoCo 的资源取舍。 [查看对应图解状态](/#/l3-r2-p14/1)[查看完整图解](/course/figures/l3-r2-p14-1.html)","sha256":"84c7ee2f6347e661790ddea3d726be5b0b903b88eef6ce31b9c2f76e979ef6e4","chapter":{"id":"I","title":"学习信号与表示"},"unit":{"id":"i-dictionary-and-updates","title":"怎样增加候选，同时让历史表示仍可比较？"},"page":{"id":"h-i-batch-candidate-matrix","title":"先看轴身份，再数每行的候选","number":1},"sectionTitle":"先看轴身份，再数每行的候选","currentQuestion":"怎样增加候选，同时让历史表示仍可比较？","sourceSlides":["l3-r2-p14"],"knowledgeBlock":null,"formulas":[],"figure":{"caption":"当前批次从原图 A、B 的 A1/A2/B1/B2 四视图（4×4）扩为 A、B、C 的六视图（6×6）。矩阵两轴使用同一视图列表，灰色斜线主对角为自身并排除；每行只有同源的另一个视图为绿色正例，其余 2N−2 个为其他候选。A1 行显示全部候选身份。右侧将复用历史 key 作为下一方法 MoCo 的资源取舍。 查看对应图解状态","labels":["全部来自当前批次","能否复用历史特征？","3 张原图 → 6 个视图","原图 A","A1","A2","原图 B","B1","B2","原图 C","C1","C2","两轴使用同一个视图列表；行表示查询","A1","+","A2","+","B1","+","B2","+","C1","+","C2","+","A1","A2","B1","B2","C1","C2","固定查询 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