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实现代码","currentQuestion":"5 · 查询依赖的交互：一个可运行的区域加权对照 · 实现代码","sourceSlides":[],"knowledgeBlock":null,"formulas":[],"previousBlock":"b-876874a6fd6a1cd20b53ca9d","nextBlock":"b-4a59297954a6661420a21236","prerequisites":[{"id":"b-e779f04a098945062e026f15","url":"#b-e779f04a098945062e026f15","role":"section-title"},{"id":"b-d773900e3717510bc22d1c45","url":"#b-d773900e3717510bc22d1c45","role":"problem-context"}],"relatedBlocks":[]},{"id":"b-4a59297954a6661420a21236","type":"pre","scope":"document","url":"https://codingai-lec03.pages.dev/course/notebook-blocks/06052931c0434d36aae2251b7873e30c.html#b-4a59297954a6661420a21236","content":"```\nR=a['relation_regions'][:,1:]  # 两图 × 两区域 × 512，丢弃full区域\n# 同一图片换查询，观察权重确实变化。\natomic=R[0]@Q[[0,2]].T\nweights=np.exp((atomic-atomic.max(0,keepdims=True))/.05)\nweights/=weights.sum(0,keepdims=True)\nprint('cat / astronaut 查询的 [左区,右区] 权重：',weights.T)\n# 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